Optimal. Leaf size=152 \[ \frac {3 a^2 c^5 \cos ^5(e+f x)}{10 f}+\frac {3 a^2 \cos ^5(e+f x) \left (c^5-c^5 \sin (e+f x)\right )}{14 f}+\frac {3 a^2 c^5 \sin (e+f x) \cos ^3(e+f x)}{8 f}+\frac {9 a^2 c^5 \sin (e+f x) \cos (e+f x)}{16 f}+\frac {9}{16} a^2 c^5 x+\frac {a^2 c^3 \cos ^5(e+f x) (c-c \sin (e+f x))^2}{7 f} \]
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Rubi [A] time = 0.20, antiderivative size = 152, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 5, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.192, Rules used = {2736, 2678, 2669, 2635, 8} \[ \frac {3 a^2 c^5 \cos ^5(e+f x)}{10 f}+\frac {3 a^2 c^5 \sin (e+f x) \cos ^3(e+f x)}{8 f}+\frac {a^2 c^3 \cos ^5(e+f x) (c-c \sin (e+f x))^2}{7 f}+\frac {3 a^2 \cos ^5(e+f x) \left (c^5-c^5 \sin (e+f x)\right )}{14 f}+\frac {9 a^2 c^5 \sin (e+f x) \cos (e+f x)}{16 f}+\frac {9}{16} a^2 c^5 x \]
Antiderivative was successfully verified.
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Rule 8
Rule 2635
Rule 2669
Rule 2678
Rule 2736
Rubi steps
\begin {align*} \int (a+a \sin (e+f x))^2 (c-c \sin (e+f x))^5 \, dx &=\left (a^2 c^2\right ) \int \cos ^4(e+f x) (c-c \sin (e+f x))^3 \, dx\\ &=\frac {a^2 c^3 \cos ^5(e+f x) (c-c \sin (e+f x))^2}{7 f}+\frac {1}{7} \left (9 a^2 c^3\right ) \int \cos ^4(e+f x) (c-c \sin (e+f x))^2 \, dx\\ &=\frac {a^2 c^3 \cos ^5(e+f x) (c-c \sin (e+f x))^2}{7 f}+\frac {3 a^2 \cos ^5(e+f x) \left (c^5-c^5 \sin (e+f x)\right )}{14 f}+\frac {1}{2} \left (3 a^2 c^4\right ) \int \cos ^4(e+f x) (c-c \sin (e+f x)) \, dx\\ &=\frac {3 a^2 c^5 \cos ^5(e+f x)}{10 f}+\frac {a^2 c^3 \cos ^5(e+f x) (c-c \sin (e+f x))^2}{7 f}+\frac {3 a^2 \cos ^5(e+f x) \left (c^5-c^5 \sin (e+f x)\right )}{14 f}+\frac {1}{2} \left (3 a^2 c^5\right ) \int \cos ^4(e+f x) \, dx\\ &=\frac {3 a^2 c^5 \cos ^5(e+f x)}{10 f}+\frac {3 a^2 c^5 \cos ^3(e+f x) \sin (e+f x)}{8 f}+\frac {a^2 c^3 \cos ^5(e+f x) (c-c \sin (e+f x))^2}{7 f}+\frac {3 a^2 \cos ^5(e+f x) \left (c^5-c^5 \sin (e+f x)\right )}{14 f}+\frac {1}{8} \left (9 a^2 c^5\right ) \int \cos ^2(e+f x) \, dx\\ &=\frac {3 a^2 c^5 \cos ^5(e+f x)}{10 f}+\frac {9 a^2 c^5 \cos (e+f x) \sin (e+f x)}{16 f}+\frac {3 a^2 c^5 \cos ^3(e+f x) \sin (e+f x)}{8 f}+\frac {a^2 c^3 \cos ^5(e+f x) (c-c \sin (e+f x))^2}{7 f}+\frac {3 a^2 \cos ^5(e+f x) \left (c^5-c^5 \sin (e+f x)\right )}{14 f}+\frac {1}{16} \left (9 a^2 c^5\right ) \int 1 \, dx\\ &=\frac {9}{16} a^2 c^5 x+\frac {3 a^2 c^5 \cos ^5(e+f x)}{10 f}+\frac {9 a^2 c^5 \cos (e+f x) \sin (e+f x)}{16 f}+\frac {3 a^2 c^5 \cos ^3(e+f x) \sin (e+f x)}{8 f}+\frac {a^2 c^3 \cos ^5(e+f x) (c-c \sin (e+f x))^2}{7 f}+\frac {3 a^2 \cos ^5(e+f x) \left (c^5-c^5 \sin (e+f x)\right )}{14 f}\\ \end {align*}
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Mathematica [A] time = 1.11, size = 89, normalized size = 0.59 \[ \frac {a^2 c^5 (665 \sin (2 (e+f x))-35 \sin (4 (e+f x))-35 \sin (6 (e+f x))+945 \cos (e+f x)+455 \cos (3 (e+f x))+77 \cos (5 (e+f x))-5 \cos (7 (e+f x))+1260 e+1260 f x)}{2240 f} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.48, size = 103, normalized size = 0.68 \[ -\frac {80 \, a^{2} c^{5} \cos \left (f x + e\right )^{7} - 448 \, a^{2} c^{5} \cos \left (f x + e\right )^{5} - 315 \, a^{2} c^{5} f x + 35 \, {\left (8 \, a^{2} c^{5} \cos \left (f x + e\right )^{5} - 6 \, a^{2} c^{5} \cos \left (f x + e\right )^{3} - 9 \, a^{2} c^{5} \cos \left (f x + e\right )\right )} \sin \left (f x + e\right )}{560 \, f} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.23, size = 154, normalized size = 1.01 \[ \frac {9}{16} \, a^{2} c^{5} x - \frac {a^{2} c^{5} \cos \left (7 \, f x + 7 \, e\right )}{448 \, f} + \frac {11 \, a^{2} c^{5} \cos \left (5 \, f x + 5 \, e\right )}{320 \, f} + \frac {13 \, a^{2} c^{5} \cos \left (3 \, f x + 3 \, e\right )}{64 \, f} + \frac {27 \, a^{2} c^{5} \cos \left (f x + e\right )}{64 \, f} - \frac {a^{2} c^{5} \sin \left (6 \, f x + 6 \, e\right )}{64 \, f} - \frac {a^{2} c^{5} \sin \left (4 \, f x + 4 \, e\right )}{64 \, f} + \frac {19 \, a^{2} c^{5} \sin \left (2 \, f x + 2 \, e\right )}{64 \, f} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.40, size = 255, normalized size = 1.68 \[ \frac {\frac {c^{5} a^{2} \left (\frac {16}{5}+\sin ^{6}\left (f x +e \right )+\frac {6 \left (\sin ^{4}\left (f x +e \right )\right )}{5}+\frac {8 \left (\sin ^{2}\left (f x +e \right )\right )}{5}\right ) \cos \left (f x +e \right )}{7}+3 c^{5} a^{2} \left (-\frac {\left (\sin ^{5}\left (f x +e \right )+\frac {5 \left (\sin ^{3}\left (f x +e \right )\right )}{4}+\frac {15 \sin \left (f x +e \right )}{8}\right ) \cos \left (f x +e \right )}{6}+\frac {5 f x}{16}+\frac {5 e}{16}\right )+\frac {c^{5} a^{2} \left (\frac {8}{3}+\sin ^{4}\left (f x +e \right )+\frac {4 \left (\sin ^{2}\left (f x +e \right )\right )}{3}\right ) \cos \left (f x +e \right )}{5}-5 c^{5} a^{2} \left (-\frac {\left (\sin ^{3}\left (f x +e \right )+\frac {3 \sin \left (f x +e \right )}{2}\right ) \cos \left (f x +e \right )}{4}+\frac {3 f x}{8}+\frac {3 e}{8}\right )-\frac {5 c^{5} a^{2} \left (2+\sin ^{2}\left (f x +e \right )\right ) \cos \left (f x +e \right )}{3}+c^{5} a^{2} \left (-\frac {\sin \left (f x +e \right ) \cos \left (f x +e \right )}{2}+\frac {f x}{2}+\frac {e}{2}\right )+3 c^{5} a^{2} \cos \left (f x +e \right )+c^{5} a^{2} \left (f x +e \right )}{f} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.82, size = 256, normalized size = 1.68 \[ -\frac {192 \, {\left (5 \, \cos \left (f x + e\right )^{7} - 21 \, \cos \left (f x + e\right )^{5} + 35 \, \cos \left (f x + e\right )^{3} - 35 \, \cos \left (f x + e\right )\right )} a^{2} c^{5} - 448 \, {\left (3 \, \cos \left (f x + e\right )^{5} - 10 \, \cos \left (f x + e\right )^{3} + 15 \, \cos \left (f x + e\right )\right )} a^{2} c^{5} - 11200 \, {\left (\cos \left (f x + e\right )^{3} - 3 \, \cos \left (f x + e\right )\right )} a^{2} c^{5} - 105 \, {\left (4 \, \sin \left (2 \, f x + 2 \, e\right )^{3} + 60 \, f x + 60 \, e + 9 \, \sin \left (4 \, f x + 4 \, e\right ) - 48 \, \sin \left (2 \, f x + 2 \, e\right )\right )} a^{2} c^{5} + 1050 \, {\left (12 \, f x + 12 \, e + \sin \left (4 \, f x + 4 \, e\right ) - 8 \, \sin \left (2 \, f x + 2 \, e\right )\right )} a^{2} c^{5} - 1680 \, {\left (2 \, f x + 2 \, e - \sin \left (2 \, f x + 2 \, e\right )\right )} a^{2} c^{5} - 6720 \, {\left (f x + e\right )} a^{2} c^{5} - 20160 \, a^{2} c^{5} \cos \left (f x + e\right )}{6720 \, f} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 9.23, size = 452, normalized size = 2.97 \[ \frac {9\,a^2\,c^5\,x}{16}-\frac {{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^2\,\left (\frac {a^2\,c^5\,\left (315\,e+315\,f\,x\right )}{80}-\frac {a^2\,c^5\,\left (2205\,e+2205\,f\,x+1792\right )}{560}\right )+{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^{12}\,\left (\frac {a^2\,c^5\,\left (315\,e+315\,f\,x\right )}{80}-\frac {a^2\,c^5\,\left (2205\,e+2205\,f\,x+3360\right )}{560}\right )+{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^4\,\left (\frac {3\,a^2\,c^5\,\left (315\,e+315\,f\,x\right )}{80}-\frac {a^2\,c^5\,\left (6615\,e+6615\,f\,x+6496\right )}{560}\right )+{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^{10}\,\left (\frac {3\,a^2\,c^5\,\left (315\,e+315\,f\,x\right )}{80}-\frac {a^2\,c^5\,\left (6615\,e+6615\,f\,x+8960\right )}{560}\right )+{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^8\,\left (\frac {a^2\,c^5\,\left (315\,e+315\,f\,x\right )}{16}-\frac {a^2\,c^5\,\left (11025\,e+11025\,f\,x+7840\right )}{560}\right )+{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^6\,\left (\frac {a^2\,c^5\,\left (315\,e+315\,f\,x\right )}{16}-\frac {a^2\,c^5\,\left (11025\,e+11025\,f\,x+17920\right )}{560}\right )-\frac {17\,a^2\,c^5\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^3}{2}+\frac {13\,a^2\,c^5\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^5}{8}-\frac {13\,a^2\,c^5\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^9}{8}+\frac {17\,a^2\,c^5\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^{11}}{2}+\frac {7\,a^2\,c^5\,{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^{13}}{8}+\frac {a^2\,c^5\,\left (315\,e+315\,f\,x\right )}{560}-\frac {a^2\,c^5\,\left (315\,e+315\,f\,x+736\right )}{560}-\frac {7\,a^2\,c^5\,\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}{8}}{f\,{\left ({\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}^2+1\right )}^7} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 10.58, size = 629, normalized size = 4.14 \[ \begin {cases} \frac {15 a^{2} c^{5} x \sin ^{6}{\left (e + f x \right )}}{16} + \frac {45 a^{2} c^{5} x \sin ^{4}{\left (e + f x \right )} \cos ^{2}{\left (e + f x \right )}}{16} - \frac {15 a^{2} c^{5} x \sin ^{4}{\left (e + f x \right )}}{8} + \frac {45 a^{2} c^{5} x \sin ^{2}{\left (e + f x \right )} \cos ^{4}{\left (e + f x \right )}}{16} - \frac {15 a^{2} c^{5} x \sin ^{2}{\left (e + f x \right )} \cos ^{2}{\left (e + f x \right )}}{4} + \frac {a^{2} c^{5} x \sin ^{2}{\left (e + f x \right )}}{2} + \frac {15 a^{2} c^{5} x \cos ^{6}{\left (e + f x \right )}}{16} - \frac {15 a^{2} c^{5} x \cos ^{4}{\left (e + f x \right )}}{8} + \frac {a^{2} c^{5} x \cos ^{2}{\left (e + f x \right )}}{2} + a^{2} c^{5} x + \frac {a^{2} c^{5} \sin ^{6}{\left (e + f x \right )} \cos {\left (e + f x \right )}}{f} - \frac {33 a^{2} c^{5} \sin ^{5}{\left (e + f x \right )} \cos {\left (e + f x \right )}}{16 f} + \frac {2 a^{2} c^{5} \sin ^{4}{\left (e + f x \right )} \cos ^{3}{\left (e + f x \right )}}{f} + \frac {a^{2} c^{5} \sin ^{4}{\left (e + f x \right )} \cos {\left (e + f x \right )}}{f} - \frac {5 a^{2} c^{5} \sin ^{3}{\left (e + f x \right )} \cos ^{3}{\left (e + f x \right )}}{2 f} + \frac {25 a^{2} c^{5} \sin ^{3}{\left (e + f x \right )} \cos {\left (e + f x \right )}}{8 f} + \frac {8 a^{2} c^{5} \sin ^{2}{\left (e + f x \right )} \cos ^{5}{\left (e + f x \right )}}{5 f} + \frac {4 a^{2} c^{5} \sin ^{2}{\left (e + f x \right )} \cos ^{3}{\left (e + f x \right )}}{3 f} - \frac {5 a^{2} c^{5} \sin ^{2}{\left (e + f x \right )} \cos {\left (e + f x \right )}}{f} - \frac {15 a^{2} c^{5} \sin {\left (e + f x \right )} \cos ^{5}{\left (e + f x \right )}}{16 f} + \frac {15 a^{2} c^{5} \sin {\left (e + f x \right )} \cos ^{3}{\left (e + f x \right )}}{8 f} - \frac {a^{2} c^{5} \sin {\left (e + f x \right )} \cos {\left (e + f x \right )}}{2 f} + \frac {16 a^{2} c^{5} \cos ^{7}{\left (e + f x \right )}}{35 f} + \frac {8 a^{2} c^{5} \cos ^{5}{\left (e + f x \right )}}{15 f} - \frac {10 a^{2} c^{5} \cos ^{3}{\left (e + f x \right )}}{3 f} + \frac {3 a^{2} c^{5} \cos {\left (e + f x \right )}}{f} & \text {for}\: f \neq 0 \\x \left (a \sin {\relax (e )} + a\right )^{2} \left (- c \sin {\relax (e )} + c\right )^{5} & \text {otherwise} \end {cases} \]
Verification of antiderivative is not currently implemented for this CAS.
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